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dc.contributor.authorFomin, Fedor
dc.contributor.authorGolovach, Petr
dc.contributor.authorLokshtanov, Daniel
dc.contributor.authorPanolan, Fahad
dc.contributor.authorSaurabh, Saket
dc.contributor.authorZehavi, Meirav
dc.date.accessioned2020-05-13T06:54:34Z
dc.date.available2020-05-13T06:54:34Z
dc.date.issued2019-09-06
dc.PublishedFomin V, Golovach P, Lokshtanov D, Panolan F, Saurabh S, Zehavi M. Going Far From Degeneracy. Leibniz International Proceedings in Informatics. 2019; Article No. 47; pp. 47:1–47:14eng
dc.identifier.issn1868-8969en_US
dc.identifier.urihttps://hdl.handle.net/1956/22211
dc.description.abstractAn undirected graph G is d-degenerate if every subgraph of G has a vertex of degree at most d. By the classical theorem of Erd\H{o}s and Gallai from 1959, every graph of degeneracy d>1 contains a cycle of length at least d+1. The proof of Erd\H{o}s and Gallai is constructive and can be turned into a polynomial time algorithm constructing a cycle of length at least d+1. But can we decide in polynomial time whether a graph contains a cycle of length at least d+2? An easy reduction from Hamiltonian Cycle provides a negative answer to this question: deciding whether a graph has a cycle of length at least d+2 is NP-complete. Surprisingly, the complexity of the problem changes drastically when the input graph is 2-connected. In this case we prove that deciding whether G contains a cycle of length at least d+k can be done in time 2^{O(k)}|V(G)|^{O(1)}. In other words, deciding whether a 2-connected n-vertex G contains a cycle of length at least d+log n can be done in polynomial time. Similar algorithmic results hold for long paths in graphs. We observe that deciding whether a graph has a path of length at least d+1 is NP-complete. However, we prove that if graph G is connected, then deciding whether G contains a path of length at least d+k can be done in time 2^{O(k)}n^{O(1)}. We complement these results by showing that the choice of degeneracy as the `above guarantee parameterization' is optimal in the following sense: For any \epsilon>0 it is NP-complete to decide whether a connected (2-connected) graph of degeneracy d has a path (cycle) of length at least (1+\epsilon)d.en_US
dc.language.isoengeng
dc.publisherSchloss Dagstuhlen_US
dc.rightsAttribution CC BYeng
dc.rights.urihttps://creativecommons.org/licenses/by/3.0/eng
dc.titleGoing Far From Degeneracyen_US
dc.typePeer reviewed
dc.typeJournal article
dc.date.updated2020-01-17T14:47:07Z
dc.description.versionpublishedVersionen_US
dc.rights.holderCopyright © Fedor V. Fomin, Petr A. Golovach, Daniel Lokshtanov, Fahad Panolan, Saket Saurabh, and Meirav Zehavien_US
dc.identifier.doihttps://doi.org/10.4230/lipics.esa.2019.47
dc.identifier.cristin1774855
dc.source.journalLeibniz International Proceedings in Informatics
dc.relation.projectNorges forskningsråd: 263317
dc.relation.projectNorges forskningsråd: 249994
dc.identifier.citationLeibniz International Proceedings in Informatics. 2019, 47.


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